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9x^2-576x+700=0
a = 9; b = -576; c = +700;
Δ = b2-4ac
Δ = -5762-4·9·700
Δ = 306576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{306576}=\sqrt{144*2129}=\sqrt{144}*\sqrt{2129}=12\sqrt{2129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-576)-12\sqrt{2129}}{2*9}=\frac{576-12\sqrt{2129}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-576)+12\sqrt{2129}}{2*9}=\frac{576+12\sqrt{2129}}{18} $
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